(k-12)x^2(k-12)x+2=0

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Solution for (k-12)x^2(k-12)x+2=0 equation: 


Simplifying
(k + -12) * x2(k + -12) * x + 2 = 0

Reorder the terms:
(-12 + k) * x2(k + -12) * x + 2 = 0

Reorder the terms:
(-12 + k) * x2(-12 + k) * x + 2 = 0

Reorder the terms for easier multiplication:
x2 * x(-12 + k)(-12 + k) + 2 = 0

Multiply x2 * x
x3(-12 + k)(-12 + k) + 2 = 0

Multiply (-12 + k) * (-12 + k)
x3(-12(-12 + k) + k(-12 + k)) + 2 = 0
x3((-12 * -12 + k * -12) + k(-12 + k)) + 2 = 0
x3((144 + -12k) + k(-12 + k)) + 2 = 0
x3(144 + -12k + (-12 * k + k * k)) + 2 = 0
x3(144 + -12k + (-12k + k2)) + 2 = 0

Combine like terms: -12k + -12k = -24k
x3(144 + -24k + k2) + 2 = 0
(144 * x3 + -24k * x3 + k2 * x3) + 2 = 0

Reorder the terms:
(-24kx3 + k2x3 + 144x3) + 2 = 0
(-24kx3 + k2x3 + 144x3) + 2 = 0

Reorder the terms:
2 + -24kx3 + k2x3 + 144x3 = 0

Solving
2 + -24kx3 + k2x3 + 144x3 = 0

Solving for variable 'k'.

The solution to this equation could not be determined.

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